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Linear Vector Fields

Dec 2, 2025

Consider a simple vector fields function $u_t(x)$, which is a simple linear function in $x$, i.e. $u_t(x) = -\theta x$ for $\theta > 0$. Then the function

\[ \psi_t(x_0) = \exp (-\theta t) x_0 \]

defines a flow $\psi$ solving the ODE.

Proof

  • Check $\psi_0(x_0) = x_0$
  • Check $\frac{d}{dt} \psi_t(x_0) = u_t(\psi_t(x_0))$